w^2+24w=3456

Solution for w^2+24w=3456 equation:

w^2+24w=3456

We move all terms to the left:

w^2+24w-(3456)=0

a = 1; b = 24; c = -3456;
Δ = b2-4ac
Δ = 242-4·1·(-3456)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-120}{2*1}=\frac{-144}{2}
=-72
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+120}{2*1}=\frac{96}{2}
=48
$